{"id":18007,"date":"2024-05-14T22:45:31","date_gmt":"2024-05-14T22:45:31","guid":{"rendered":"https:\/\/soicau5016.minhngocxoso.com\/?p=18007"},"modified":"2024-05-14T22:45:31","modified_gmt":"2024-05-14T22:45:31","slug":"phuong-phap-danh-dan-de-16-so-khung-5-ngay-don-gian-hieu-qua-nhat","status":"publish","type":"post","link":"https:\/\/soicaudanlovip.com\/phuong-phap-danh-dan-de-16-so-khung-5-ngay-don-gian-hieu-qua-nhat\/","title":{"rendered":"ph\u01b0\u01a1ng ph\u00e1p \u0111\u00e1nh d\u00e0n \u0111\u1ec1 16 s\u1ed1 khung 5 ng\u00e0y \u0111\u01a1n gi\u1ea3n, hi\u1ec7u qu\u1ea3 nh\u1ea5t"},"content":{"rendered":"
<\/p>\n\n\n
\u0110\u00e1nh d\u00e0n \u0111\u1ec1 16 s\u1ed1 \u0111\u01b0\u1ee3c \u0111\u00e1nh gi\u00e1 l\u00e0 m\u1ed9t trong nh\u1eefng c\u00e1ch gi\u00fap ng\u01b0\u1eddi ch\u01a1i d\u1ec5 d\u00e0ng tr\u00fang \u0111\u1ec1 h\u01a1n, nh\u1ea5t l\u00e0 \u0111\u1ed1i v\u1edbi nh\u1eefng ng\u01b0\u1eddi m\u1edbi nh\u1eadp m\u00f4n. Tuy v\u1eady, kh\u00f4ng ph\u1ea3i ai ch\u01a1i d\u00e0n \u0111\u1ec1 c\u0169ng s\u1ebd th\u00e0nh c\u00f4ng, b\u1edfi v\u00ec \u0111\u1ec3 c\u00f3 \u0111\u01b0\u1ee3c d\u00e0n s\u1ed1 \u0111\u1ec1 ch\u00ednh x\u00e1c th\u00ec c\u1ea7n r\u1ea5t nhi\u1ec1u th\u1eddi gian nghi\u00ean c\u1ee9u. Hi\u1ec3u \u0111\u01b0\u1ee3c \u0111i\u1ec1u \u0111\u00f3, \u0111\u1ec3 gi\u00fap ng\u01b0\u1eddi ch\u01a1i kh\u00f4ng t\u1ed1n qu\u00e1 nhi\u1ec1u th\u1eddi gian, ch\u00fang t\u00f4i s\u1ebd g\u1ee3i \u00fd nh\u1eefng c\u00e1ch nu\u00f4i d\u00e0n \u0111\u1ec1 16 s\u1ed1 khung 5 ng\u00e0y si\u00eau hi\u1ec7u qu\u1ea3 trong b\u00e0i vi\u1ebft n\u00e0y. C\u00f9ng t\u00ecm hi\u1ec3u ngay nh\u00e9<\/p>\n\n\n\n
D\u00e0n \u0111\u1ec1 16 s\u1ed1 hi\u1ec3u \u0111\u01a1n gi\u1ea3n l\u00e0 b\u1ea1n s\u1ebd nu\u00f4i c\u00f9ng l\u00fac 16 con \u0111\u1ec1 trong t\u1ed5 h\u1ee3p t\u1eeb 00 – 99, c\u00f3 th\u1ec3 c\u00f3 s\u1ef1 li\u00ean quan \u0111\u1ebfn nhau, ho\u1eb7c l\u00e0 kh\u00f4ng. C\u00f3 th\u1ec3 th\u1ea5y, \u0111\u00e2y l\u00e0 ph\u01b0\u01a1ng ph\u00e1p \u0111\u00e1nh nhanh, th\u1eafng nhanh, m\u00e0 c\u00e1ch th\u1ef1c hi\u1ec7n th\u00ec r\u1ea5t \u0111\u01a1n gi\u1ea3n.<\/p>\n\n\n\n
Hi\u1ec7n nay, h\u00ecnh th\u1ee9c nu\u00f4i d\u00e0n \u0111\u1ec1 16 con khung 5 ng\u00e0y \u0111ang \u0111\u01b0\u1ee3c nhi\u1ec1u ng\u01b0\u1eddi l\u1ef1a ch\u1ecdn nh\u1ea5t, tuy nhi\u00ean t\u1ed1n kh\u00e1 nhi\u1ec1u th\u1eddi gian. Ng\u01b0\u1eddi ch\u01a1i c\u1ea7n b\u1ecf th\u1eddi gian ra \u0111\u1ec3 ph\u00e2n t\u00edch v\u00e0 t\u1ed5ng h\u1ee3p th\u00f4ng tin, r\u1ed3i \u0111\u01b0a ra m\u1ed9t d\u00e0n \u0111\u1ec1 ch\u00ednh x\u00e1c, chu\u1ea9n nh\u1ea5t.<\/p>\n\n\n\n
D\u00e0n 16 s\u1ed1 khung max 5 ng\u00e0y theo t\u1ed5ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u0169ng l\u00e0 m\u1ed9t trong nh\u1eefng ph\u01b0\u01a1ng ph\u00e1p kh\u00e1 h\u1eefu hi\u1ec7u. \u0110\u1ec3 c\u00f3 th\u1ec3 s\u1eed d\u1ee5ng \u0111\u01b0\u1ee3c ph\u01b0\u01a1ng ph\u00e1p n\u00e0y, ng\u01b0\u1eddi ch\u01a1i c\u1ea7n ph\u1ea3i theo d\u00f5i k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 th\u01b0\u1eddng xuy\u00ean, t\u1eeb \u0111\u00f3 s\u1ebd l\u1ef1a ch\u1ecdn \u0111\u01b0\u1ee3c ra nh\u1eefng con s\u1ed1 trong d\u00e0n \u0111\u1ec1 c\u1ea7n ch\u01a1i. Ti\u1ebfp theo, ch\u00fang ta s\u1ebd l\u1ea5y t\u1ed5ng c\u1ee7a 2 s\u1ed1 cu\u1ed1i c\u00f9ng trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t m\u00e0 ta th\u1ea5y \u0111\u1eb9p nh\u1ea5t trong 5 ng\u00e0y theo d\u00f5i k\u1ebft qu\u1ea3, \u0111\u1ec3 t\u1ea1o th\u00e0nh d\u00e0n \u0111\u1ec1 16 con nu\u00f4i khung 5 ng\u00e0y.<\/p>\n\n\n\n
V\u00ed d\u1ee5, Ta c\u00f3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t ng\u00e0y 5\/3 l\u00e0 15612, t\u1ed5ng c\u1ee7a 2 s\u1ed1 cu\u1ed1i c\u00f9ng l\u00e0 1 + 2 = 3. V\u1eady khi n\u00e0y ch\u00fang ta s\u1ebd c\u00f3 \u0111\u01b0\u1ee3c d\u00e0n \u0111\u1ec1 t\u1ed5ng 3 bao g\u1ed3m 16 con s\u1ed1 \u0111\u00f3 l\u00e0 03, 13, 12, 21, 49, 94, 58, 85, 67, 76 v\u00e0 6 s\u1ed1 \u1edf gi\u1ea3i \u0111\u1eb7c bi\u1ec7t 15, 51, 16, 61, 56, 65.<\/p>\n\n\n\n
Ph\u01b0\u01a1ng ph\u00e1p m\u00e0 nu\u00f4i d\u00e0n \u0111\u1ec1 theo \u0111\u1ea7u 0 \u0111u\u00f4i 0 n\u00e0y s\u1ebd gi\u00fap anh em t\u00ecm ra \u0111\u01b0\u1ee3c nh\u1eefng con s\u1ed1 \u0111\u1eb9p kh\u00e1 \u0111\u01a1n gi\u1ea3n. Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u00f3 \u0111\u1ed9 ch\u00ednh x\u00e1c c\u1ef1c cao, do \u0111\u00f3, ch\u00fang ta c\u00f3 th\u1ec3 d\u1ef1a v\u00e0o \u0111\u00f3 \u0111\u1ec3 thu \u0111\u01b0\u1ee3c ti\u1ec1n t\u1ef7 nhanh ch\u00f3ng.<\/p>\n\n\n\n
Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u0169ng \u0111\u00f2i h\u1ecfi anh em c\u1ea7n ph\u1ea3i th\u01b0\u1eddng xuy\u00ean theo d\u00f5i c\u00e1c gi\u1ea3i \u0111\u1eb7c bi\u1ec7t XSMB. Trong tr\u01b0\u1eddng h\u1ee3p xu\u1ea5t hi\u1ec7n gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u00f3 s\u1ed1 0 xu\u1ea5t hi\u1ec7n \u1edf gi\u1eefa, th\u00ec t\u1ef7 l\u1ec7 cao con l\u00f4 c\u00f3 \u0111\u1ea7u 0 \u0111u\u00f4i 0 s\u1ebd n\u1ed5 trong v\u00f2ng t\u1eeb 1 cho \u0111\u1ebfn 5 ng\u00e0y ti\u1ebfp theo.<\/p>\n\n\n\n
Khi \u0111\u00f3 d\u00e0n \u0111\u1ec1 16 s\u1ed1 ta c\u00f3 th\u1ec3 t\u1ea1o \u0111\u01b0\u1ee3c \u0111\u1ec3 nu\u00f4i khung max 5 ng\u00e0y \u0111\u00f3 l\u00e0 00, 01, 10, 02, 03, 04, 40, 05, 06, 07, 08, 09, 20, 30, 50, 60.<\/p>\n\n\n\n
T\u01b0\u01a1ng t\u1ef1 v\u1edbi ph\u01b0\u01a1ng ph\u00e1p theo t\u1ed5ng \u0111\u1eb7c bi\u1ec7t, ch\u1ec9 kh\u00e1c l\u00e0 ph\u01b0\u01a1ng ph\u00e1p n\u00e0y ta s\u1ebd t\u00ecm ra nh\u1eefng con s\u1ed1 \u0111\u1eb9p theo hi\u1ec7u \u0111\u1eb7c bi\u1ec7t. Anh em ch\u00fang ta c\u1ea7n ph\u1ea3i c\u00f3 s\u1ef1 t\u00ednh to\u00e1n k\u1ef9 l\u01b0\u1ee1ng \u0111\u1ec3 mang l\u1ea1i hi\u1ec7u qu\u1ea3 cao nh\u1ea5t.<\/p>\n\n\n\n
C\u00e1ch th\u1ef1c hi\u1ec7n nh\u01b0 sau, ng\u01b0\u1eddi ch\u01a1i s\u1ebd theo d\u00f5i b\u1ea3ng k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed5 c\u00f4ng b\u1ed1 v\u00e0o th\u1ee9 5 h\u00e0ng tu\u1ea7n. Sau \u0111\u00f3 ta s\u1ebd l\u1ea5y hi\u1ec7u c\u1ee7a 2 s\u1ed1 cu\u1ed1i c\u00f9ng gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a ng\u00e0y h\u00f4m \u0111\u00f3 \u0111\u1ec3 l\u00e0m con s\u1ed1 t\u1ea1o d\u00e0n \u0111\u1ec1.<\/p>\n\n\n\n
V\u00ed d\u1ee5, k\u1ebft qu\u1ea3 gi\u1ea3i \u0111\u1eb7c bi\u1ec7t h\u00f4m th\u1ee9 5 l\u00e0 42050, ta s\u1ebd l\u1ea5y 2 s\u1ed1 cu\u1ed1i c\u00f9ng tr\u1eeb cho nhau \u0111\u01b0\u1ee3c hi\u1ec7u 5 \u2013 0 = 5. T\u1eeb \u0111\u00f3, ta s\u1ebd c\u00f3 d\u00e0n \u0111\u1ec1 16 con bao g\u1ed3m c\u00e1c c\u1eb7p l\u00f4 05, 15, 25, 35, 45, 55, 65, 75, 85, 95, 50, 42, 24, 20, 02 \u0111\u1ec3 nu\u00f4i.<\/p>\n\n\n\n
N\u1ebfu con s\u1ed1 n\u00e0o trong d\u00e3y 16 s\u1ed1 \u0111\u00f3 trong v\u00f2ng 5 ng\u00e0y n\u1ed5 th\u00ec anh em n\u00ean nu\u00f4i l\u1ea1i d\u00e0n \u0111\u1ec1 16 s\u1ed1 kh\u00e1c.<\/p>\n\n\n\n